coaster final height

Good explanation. I think it's pretty much a given that it will be a parabolic top hat. I never really considered the difference in centripetal acceleration between a parabolic top hat and a circular top hat (a = v^2 / r) but I do see that now.

By the way, I like the name. ;)

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L-TH-TW-B... "Meh"
Wicked twists: 11
*** This post was edited by Majin Heero 11/19/2002 12:26:14 AM ***

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CP_bound said:
Then why are all other coasters built by oversees companies for U.S. parks manufactured in emperical numbers?

It's all about the customer and what they want it to be. I don't think that they slate MF as being 94.41624365... meters tall. They go by feet because it's for an American park. They go by metric numbers for other countries.

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Launch: Tophat: Twistage: Brakes...

...Denial is an ugly thing.

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There is a difference between the 'press' height of a structure and the actual height. Whether they state it in meters or feet, they're gonna round it off a bit. Your not likely going to see 309'-7-4/64" either...I'm saying it's likely designed in metric, not marketed in metric.

I was just looking at intamin web site and look at this what they said,

Intamin AG are one of the leading manufacturers of thrill rides in the world, and c laim to offer the newest rides which many thought were un-feasible. Intamin invented the River Rapids ride and also holds many other accolades:First Coaster to Reach 100mph
First Coaster to Feature 8 Inversions
First Coaster to Feature 10 Inversions
First Full-Circuit Coaster to Reach 300ft Tall
First Launched Inverted Coaster
First Plug and Play Wooden Coaster Track

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First Full-Circuit Coaster Over 400ft Tall (Watch This Space!)
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Are they talking about the new ride at cedar point I think they are what do you think?

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Live to ride ride to live
What's life without rollercoasters!!!
*** This post was edited by Carsten16 11/19/2002 2:57:01 AM ***

Man, this is the third time I have had to say this. The site you are quoting Carsten is not Intamin's site. It is someone's idea of their own joke or speculation. I am sure you found this crap here: http://www.coasterforce.com/intamininfo.htm not at Intamin's real website here: http://www.intaminworldwide.com

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cyberdman

I agree with the argument regarding a parabolic top hat. Circular was simpler to calculate, but parabolic makes it even taller! That is a good thing.

Regarding comments about the lens distortion: My approach regarding the horizon eliminates the lens distortion factor since everything (including the horizon) is distorted. Therefore, a straight line from the camera to the horizon "cuts" any object between the two at the height of the camera. Assuming the camera is at 240', the horizon delineates a plane at the 240' level. This height is pretty close based on where this plane intersect MF. This can then be used to "dimension" the rest of #16, regarless of any other distance factor, angle, or lens distortion

By the way the twist on the brake side fo the tower is progressing, it appears that the track will be over the seventh level before it will stop twisting. Also there is a peice of track that ends the twist going to straight track for the end of the twist.

There are five peices of track that make the 180 degree turn for the tophat.

This is the lowest peice of the tophat, one one end, it's pretty much straight, and on the other, it's a convex parabolic curve. Picture: http://www.setecx.com/pics/cp101202const/imagepages/PICT0151.html

The three other peices, are the two peices of the body of the tophat, and the crown. In this next picture, the crown is the first peice of track, and the two behind it are the 'body' peices. http://www.setecx.com/pics/cp102602const/imagepages/PICT0230.html

I estimate that the tophat alone will be about 40 feet. Assuming that the seventh level will be about 350' and there will be one 20' peice of track above that to exit from the twist. There will probably be a stobe light and a lightening rod, which will add another 5' - 10'. Adding that up makes 415' - 420'. I think the levels are slightly over 50', so my estimate is more likely lower than higher than the actual height. The announcement might give exact stats, but most guesstimates, educated or not, are pretty much in the same ballpark. Having said that, I'm very confident that #16 will be between 400' and 450'

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House of Tomorrow: Only technology makes live worth living

The final height of the coaster will be over 400 feet. CP will own the first complete cirrcut 400 foot plus coaster, accept this. Odds are it will be around 425 feet because they probably learned their lesson with Millenium Force. They don't want the ride record to be beat so quickly this time, like MF was with the coaster in Japan and only by a lousy eight feet to. That's way it should be around 425 feet. Also a height of this can be reached at a speed between 100 and 120 mph. Depending on train length and weight, so accept that also.

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Wicked Twister is a great ride! Just because it looks simple soesn't mean it sucks! I wouldn't mind having it in my back yard!

Just a note. All Peices are there including the trains.

Hi new to this just moved to Ann Arbor from Orlando. About the Webcam thing, I don't know how the one at CP is, but I used to work at the Hulk at IOA and we had a webcam on top of dr doom that was controled by a motor and a joystick type thing like a security camera. Maybe thats how they adjust it so maybe its position has nothing to do with the final height of the ride.
*** This post was edited by Matthew Hatfield 11/19/2002 2:10:14 PM ***

From Orlando TO Ann Arbor? Why?

Maybe he likes snow? Besides, he's much closer to CP now. Welcome to the wonderful state of Michigan, Matthew.
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I'd rather die living than live like I'm dead

For love. You know how powerful that can be.

Does anyone have the NoLimits coaster simulator? It is simply THE best coaster building program in the world. It is a CAD based editor so its a little hard to get used to, but the 3D rendering of the simulator is pretty awesome. Anyway, someone designed what they thought the new coaster will be like and I think its pretty likely. He has it a 453 ft tall with a top speed of about 124 mph. (the speed might be a little high.) You can download the program at nolimits.de and the full version is $25. To download the track design go to coastersims.com and download the design called "top speed"

You may want to check out www.coasterbuzz.com Jeff (our illustrious webmaster) runs Coasterbuzz as well and has a forum for NoLimits there.

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I'd rather die living than live like I'm dead

Hey, I'll be moving to Ann Arbor next year (U-M). Of course, I already live in Michigan...

Yeah, most people here are familiar with No Limits. Like OldCPer said, check out Coasterbuzz, GTTP's sister-site, or even more specifically, check out Coasterbuzz Games.

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L-TH-TW-B... "Meh"
Wicked twists: 11

Get Hyper Rails. www.hyperrails.com i got it, its heavily cad based, very complex, but amazing. i made a millenium force sort of. same height, same angle, and the speed is exactly the same as MF really reaches. give it a try.

Is hyper rails a game? If it is is it better than roller coaster tycoon?

As far as the parabolic tophat thing, it'll be that, but of course more complex, considering that parabolas never reach vertical.

Hey, if it were a pure parabola at the top, it would be infinitely tall and take forever to ride (heck, it'd take forever to even reach the peak). That'd shut up people complaining about how short it'll be:)

-albert

I just want to add my insight as to how high this thing will be. Using a few simple physics equations you can determine how high theoretically this thing will go not taking into account wind resistance and friction.

You first need to take an arbitrary speed lets use 100mph and we need to then convert it to m/s

thus 100mph * (5280ft/1mi)(1m/3.28ft)(1ht/3600s) =

44.71544repeating m/s

then the first equation is to find the time that it takes for the train to go from its inital velocity of 44.71544m/s to 0 at which will be the maximum height for that we use the formula:

vy = vyo - gt

where vy is our ending velocity 0
vyo is our initial velocity 44.71544m/s
g is acceleration due to gravity 9.8m/s^2
t is time in seconds

plug in the numbers that we know which is everything except time which is what we are trying to find

0 = 44.71544m/s - 9.8m/s^2 * t

then -44.71544m/s = -9.8m/s^2 * t

then -44.71544m/s / -9.8m/s^2 = t

solve for t we get t = 4.56280

then we have to find height now that we know time so to do that we use this equation

y = 1/2gt^2

where y is the maximum height for the time
g is the gravity constant 9.8m/s^2
t is the time

plug them into the above equation and you get

y = 1/2 * 9.8m/s^2 * (4.56280s^2)

then y = 102.01383m

then you have to convert back to feet so you multiply by 3.28

102.01383m * (3.28m/1ft) = 334.60538ft high

now like I said this is not accounting for wind resistance but the numbers below which were derived from the same steps above will give you an idea of the height

100mph = 334.6ft
105mph = 368.9ft
110mph = 404.9ft
115mph = 442.5ft
120mph = 482.6ft

now also remember that these heights are from ground level. You also have to add the height of the track at launch and subtract for wind resistance and friction. Then you will get a final height. You can check my math but I am pretty sure that it is correct.

so this ride can get up to 400 feet going at 120mph

-Doug-

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I am a Mechanical Engineering major not an english major so pardon my horrible grammer
*** This post was edited by psycho691371 11/19/2002 11:23:18 PM ***

Yeah, well we pretty much know that it will be 400-450 feet and around 110-120 mph, so what we really need are specifics, and physics can only get these if we know things such as the drag coefficient, coefficient of friction, and mass of a train, which we don't. But thanks for making those calculations anyways, they do prove that the 400 feet can be accomplished.

By the way, you can really merge those two equations into one... y = (v^2 - vo^2 / 2g) :)

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L-TH-TW-B... "Meh"
Wicked twists: 11
*** This post was edited by Majin Heero 11/20/2002 12:07:06 AM ***

however you really dont need weight since gravity pulls down the same no matter what the weight is.

-Doug-
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I am a Mechanical Engineering major not an english major so pardon my horrible grammer