cyberdman said:
Doesn't it make more sense to type: m/s^2 or m/s*s rather than m/s/s?
So the answer then would be no. Without the parentheses, your m/s*s notation is not only misleading, but incorrect. And as far as being nitpicky, I do believe it was your post that started it and your post that asked for commentary on it. I'll stick with m/s^2 for clarity, but what do I know...
Cyberdman, if I wanted to be nitpicky, I would point out your misuse of "parenthesis" in your second post. But I won't because I did figure out what you really meant.
Mr. Point said:
Now the cost of MF is 1.5min/1sec. That's 75% cheaper than TTD. So technically, you have to wait longer for TTD than MF.Math is so fun, isn't it? See, I'm smarter than you think.
I have no idea what you just said but why wouldn't 6 trains compared to MF 3 effect the outcome of the time needed to wait for TDD?
jdubya said:
Cyberdman, if I wanted to be nitpicky, I would point out your misuse of "parenthesis" in your second post. But I won't because I did figure out what you really meant.
Please do try to educate me further. There are no problems with my second post. No parenthesis needed.
I still prefer m/s^2 - that is meters per second squared. You guys may have learned it that way, but I sure have never heard the force of gravity referred to as 9.8 meters per second per second. That just doesn't sound right.
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cyberdman
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Teenie Weenie the Giggle Queenie!
Wicked Twister Crew 2002
I saw the Name first!
Acceleration is rate of change of velocity over time, so if something accelerates at 9.8 m/s^2, then its velocity changes at a rate of 9.8 m/s every second, thus the 9.8 m/s/s notation.
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Dragster "Top Thrills": 0
World's first strata-coaster!
Basically, convert the kinetic energy of the incoming train into potential energy for the launch of the next outgoing train...the only costs in running the ride would be for maintenance, staff, and the energy losses due to friction during the ride - a very cheap way to run a very good ride!
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Steve
"Will all those who expressed disappointment at the new ride please leave the park now"
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Is that a pen?!
Yes, you're right that the acceleration will decrease as the train is launched - but this will only be noticeable if the volume of the pressure tank + the expanded launch piston is significantly bigger than the volume of the pressure tank on its own. (I'm using a piston model, but the principles still apply even if there are turbines driving cables)
If the pressure tank has a volume of 1000 cu ft, but the expanded piston has a volume of say, 1 cu ft, then the pressure before and after launch will be pretty well constant...which would mean (almost) constant acceleration or deceleration.
Additionally, if the "deceleration" piston had a smaller surface area (but longer travel) than the "acceleration" piston, then the deceleration would be slower than the acceleration (roughly in proportion to the surface areas of the two pistons).
Once the pressure tank had been charged, it would only need to be re-charged to account for energy losses incurred on each cycle, so a valve could seal the tank from the pump during the braking.
I'm not espousing the practicality of the idea, just commenting that a ride such as this could (in theory, anyway) cost very little to run.
I hope those magnetic brakes (both on the train and the track) have some serious heat-sinks on them, because they are going to be absorbing HUGE amounts of energy. This is probably another good reason for the high number of trains - more cool-off time between each train hitting the brakes.
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Steve
"Will all those who expressed disappointment at the new ride please leave the park now"
*** This post was edited by Panman 1/14/2003 6:11:04 PM ***
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