Sorry if this question has been asked before, kind of searched, but don't really know what to search for... Anyway, my cousin and I were comparing a launch of on aircraft carrier in comparison to the launch on TTD. Everywhere always states the time, instead of the length of the launch track. I mean, you could guesstimate, but I'm curious if anyone knows the exact length of the launch track?
The 600 foot figure is reasonable for the distance from the launch position to hydraulic room, but the actual portion of the launch track that is used for accelerating the train is just under 350 feet. That is where the catch car brakes start (half way through the 9th piece of launch track). The rest is used for bringing the catch car to a stop.
Maverick '07 Crew (1, 2, 3, 4, 5...oh no...)
Los Alamos National Lab '04-'07 (LoA to finish Masters Degree)
TTD '03 Crew (76 Launches - 71 Complete Circuits)
Yes, but you're talking about the same book that, in 2005, said that Top Thrill Dragster seated 10 rows of passengers, 4 across, with three 36 passenger trains... I don't know what's worse, the fact that it has 6 trains and doesn't seat 4 across, or that 10 times 4 is not 36... :)
2007: Millennium Force, 2008: Millennium Force ATL, 2009: Top Thrill Dragster
www.pointpixels.com | www.parkpixels.com
Well, you know they like to be very precise.... ;)
Like how it lists all the coasters' speeds and then for Wildcat it says "varies throughout ride." :)
2007: Millennium Force, 2008: Millennium Force ATL, 2009: Top Thrill Dragster
www.pointpixels.com | www.parkpixels.com
Hmm... It says "speed varies" on the website for both of them too.
2007: Millennium Force, 2008: Millennium Force ATL, 2009: Top Thrill Dragster
www.pointpixels.com | www.parkpixels.com
Assuming the launch goes as advertised (120MPh in 4 seconds):
120MPh = 53.645 Meters Per Second
Acceleration = Velocity / Time
Acceleration = (53.645m/s)/4s
Acceleration = 13.41125m/s²
x = (initial velocity)(time) + (1/2)(acceleration)(t²)
x = (0m/s)(4s) + (1/2)(13.41125m/s²)((4s)²)
x = 107.29 meters
107.29 meters = 352 feet
This of course assumes the acceleration is constant the whole time, which it isn't. But it's close. :)
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