Not yet, anyway. IMO.
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"If we go any faster, she'll blow apart for sure!"
Assuming no air resistance, no friction, height of 420 feet (128.016 m), ground level launch, and final velocity of 0 m/s, we can use the following acceleration/displacement equation to find the speed needed to reach the top:
vf^2=vi^2 + 2ad, where vf=final velocity (0 m/s), vi=initial velocity (unknown), a=g (acceleration due to gravity)=9.8 m/s/s, and d=displacement (420 feet, or 128.016 m)
So we get:
0^2 = vi^2 + 2(-9.8)(128.016)
0 squared = 0, and 2 x -9.8 x 128.016 = -2509.1136, so:
0 = vi^2 - 2509.1136
Add 2509.1136 to get vi^2 by itself, so:
2509.1136 = vi^2
Solve for vi by finding the square root of 2509.1136, so:
50.097 = vi (m/s)
This is in meters per second, so convert to mph so dumb Americans can understand:
112.05 mph.
This confirms jdoty's post... 112.05 mph minimum to reach the top of a 420 foot tall top hat.
PHYSICS=PHUN
Edit: I'm slow... Mox also came up with an equation in the time I took to finish mine :)
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Tommy Penner - Variable X
Cedar Point FanBoy since 2001. || Cruiser Boy since 2002.
"Pessimistic people are the happiest people on the planet. They're either right or pleasantly surprised."
*** This post was edited by MiLLeNNiuMRiDeR 10/13/2002 8:53:49 PM ***
You be daft, Man!
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"If we go any faster, she'll blow apart for sure!"
Once air resistance and friction are thrown in, I'm sure a 120+ MPH launch isn't out of the question (or Draegs' 117 MPH)
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Tommy Penner - Variable X
Cedar Point FanBoy since 2001. || Cruiser Boy since 2002.
"Pessimistic people are the happiest people on the planet. They're either right or pleasantly surprised."
Soon. Very soon. Like in a year or 2...:D
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"If we go any faster, she'll blow apart for sure!"
And 100 mph isn't safely do-able yet? Tell that to SFMM and S:TE, and Fujikyu's Dodonpa.
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Tommy Penner - Variable X
Cedar Point FanBoy since 2001. || Cruiser Boy since 2002.
"Pessimistic people are the happiest people on the planet. They're either right or pleasantly surprised."
v^2 = Vo^2 + 2a(Yo-Y)
40^2 = 0^2 =2(9.8)(Yo-0)
1600 = 19.6(Yo)
81.63 m = Y >>>267.75 ft
One of the reasons we are thinking 400+ feet is because the people "in the know" haven't shot it down. In fact, quite the contrary.
If you are militant about claiming that it won't exceed 100 mph, then you might as well claim it to be a reverse free-fall. :)
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June 28th: LocoBazooka Tour (Sevendust headlining)
July 11th: Korn, Puddle of Mudd, and Deadsy
*** This post was edited by CP_bound 10/13/2002 11:39:06 PM ***
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House of Tomorrow: Only technology makes live worth living
Those equations are all OK to use, however...
You have to consider a few things. The initial height is not 0. In fact, Jeff has hinted at an initial height (end of launch track and point of top speed) of as much as 50 or 60 feet. So that takes the necessary speed down a little bit. Of course, you also have to consider the final velocity (at the top of the top hat), which would not be 0 (as MillenniumRider has pointed out), but instead maybe 5-10 mph(?). This will bring the necessary speed up a bit. The final thing, as has been mentioned, is that you have friction and air resistance that will slow the train down, and bring the speed up a tad more.
Also, it is possible that the top speed won't be the launch speed, but rather the pullout speed. This would be the case if the pullout was at a lower height than the pullup.
By the way, whoever used conservation of energy - kudos! I haven't seen anyone use that concept yet with this new coaster. :)
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AP Physics II is where it's at!
Wicked twists: 10
Danger: Hgih Voltage!
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June 28th: LocoBazooka Tour (Sevendust headlining)
July 11th: Korn, Puddle of Mudd, and Deadsy
And yes, Physics Day will be a mad house... There's a bunch of CP virgins in my Physics class :) I'll show them how to do the Point ;)
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Tommy Penner - Variable X
Cedar Point FanBoy since 2001. || Cruiser Boy since 2002.
"Pessimistic people are the happiest people on the planet. They're either right or pleasantly surprised."
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