positives of Maverick

This is gonna be one hell of a coaster I can not wait to ride it! I am also very happy that they are theming it quite heavily, just wish the ground wasnt grassy green and looked more like sand... w00t

I wouldn't call this a heavily themed coaster. Lightly themed is more accurate.

J2K, they are both commonly referred to as "heartline rolls" and "zero-g rolls".

They both follow the heartline, and both provide a feeling of weightlessness.

Have you ever been on an Intamin with a Zero-G/Heartline roll? It's pretty obviously "weightless" feeling, and pretty cool.

Been on V:TBC at PKD. You do feel weightless, but technically, you are not weightless. What you are really feeling is your weight shift from top to side to bottom to side back to top very quickly. For true 0g you need a parabola curve that follows the trajectory of the train. For less than 0g, you need the curve to pull down before the train would peak the hill based on its trajectory.

On that recent coaster show, didn't they say that all the new coasters are designed around the heartline? That's why they're less strenuous and rough? Maybe I missed something there.

I really with there was more information on how new coasters are made, designed, etc... I'd love to do some reading on that. I'm guessing since the industry is so competitive, they don't want to delve into that too much. But, I find it all fascinating.

JuggaLotus said:
The fact that in 2003 (and still) there were at least 5 coasters better than TTD (just at CP) proved that records aren't everything. I didn't need to wait 2 years to find that out.

It's all based on opinion. Now back to the topic...

What's a negative about Maverick? That is the real question! :)

Records only bring bragging rights and that's it.

Postives

- it's the 17th coaster - another ride to add to the goal of getting on in one day!

- I think it will be awesome to ride at night

negative - it won't open until May of next year :)

I can't complain - It is a coaster - looks to be a great one at that. If I spent $21M on a coaster I would hope it would live to the audiences expectations - but that isn't always the case...

halltd said:
On that recent coaster show, didn't they say that all the new coasters are designed around the heartline? That's why they're less strenuous and rough? Maybe I missed something there.

Most of the manufacturers do that these days. Any company that works with Werner Stengal builds they're rides in this manner. I believe that Vekoma still does things the way Arrow used to, rotate the track around the rails. Which is an easier way to design and fabricate the track. With manufacturing becoming more and more based on CNC equipment, you can pretty much bend track anyway you want now.

By the way, if you want a positive of Maverick, check out the first drop on the webcam!

I cannot wait to ride this behemoth of "fun-ness", that horseshoe looks disgustingly awesome. After hearing about Maverick I new that I needed to join a coasterholics anonymous program, because I would be addicted to this ride if I did not.

I never took physics however, if 9 cars on one train on Millennium Force dive 80 degrees for 310 feet, then you get a certain amount of drop time (or air time.)
Then you have 3 cars for one train on Maverick at 95 degrees for 100ft.
Because Mavericks train is 1/3 of MF train the air time or drop time would appear to be the same, because the height difference of Maverick to MF is "also" about 1/3; 310/3 would be 103.3. See they're almost the same.
However the droptime isn't the same because of 15 more degrees in the angle of Maverick. O well, I don't know where to go from here.

^You have to consider the velocity into that equation.

Actually, A zero-g roll and a heartline roll are two different elements. Eventhough the terminology is often interchanged.

Both elements do rotate around a "heartline" as does every rotational manuever on any modern coaster. However, the principle does not place the rotational axis on the rider's hearts as often said. That would be impossible as there are two riders in a row and there cannot be two parallel axes of rotation on one rigid object (the train cars & riders are concidered a rigid object in a physical model [the only way it wouldn't is if the train fell apart or if a rider fell out...or apart:)]).

The "heartline" is positioned horizontally in the middle of the track and offset perpendicularlly from the base of the track following an approximation of the height of riders hearts. So in truth, the heartline passes in between the riders. This means that there are some vertical Gs (+ and -) involved with the start and end of any roll or bank even if the track does not change direction. Also, there are lateral Gs experienced in a outward radial direction centering on the "heartline" throughout the entire rotation. Using this logic could explain exits's experience. Because the heartline is horizontally in the middle of the train, this creates a mirrored rotational experience from one side to an other.

However, from a center-of-mass standpoint, J2k95 is correct. A heartline roll experiences 1 G throughout the element. What he did not mention was that the relative direction of that acceleration to the rider changes direction from positive to lateral to negative and the rest of the way around. Where as a Zero-G Roll pulls the same rotation around the heartline but adds a hill in the shape of the theoretical trajectory at a given speed and angle of ascent.

Thats the best I can do without bustin out formulae.

I mentioned the relative direction to the rider in a later post. ;)

SteelRaptor, In order to figure out how much "air time" you will feel, you would need to know the radi of the hills in question, the initial speed of the train as it crests the hill, the angles included in the radi, and the mass of the train.

halltd said:
Positives: Its a new coaster. :)

Its about time!LOL;)

SteelRaptor said:
I cannot wait to ride this behemoth of "fun-ness", that horseshoe looks disgustingly awesome. After hearing about Maverick I new that I needed to join a coasterholics anonymous program, because I would be addicted to this ride if I did not.

I never took physics however, if 9 cars on one train on Millennium Force dive 80 degrees for 310 feet, then you get a certain amount of drop time (or air time.)
Then you have 3 cars for one train on Maverick at 95 degrees for 100ft.
Because Mavericks train is 1/3 of MF train the air time or drop time would appear to be the same, because the height difference of Maverick to MF is "also" about 1/3; 310/3 would be 103.3. See they're almost the same.
However the droptime isn't the same because of 15 more degrees in the angle of Maverick. O well, I don't know where to go from here.

Let me see if i can help your understanding.

First off, mass has no effect on gravitational accelleration at all. Every object inside a mile of sea level wants to fall at 32 feet per second and increase a speed of +32 feet per second every second that passes or 32ft/s^2. However, in a real scenario not everything does. This is only because of resistance of air or "drag". To minimize drag you can either make the object more aerodynamic or heavier (however increased weight only works in reducing drag in a falling object).

So what we can conclude is that the train size being 1/3 the car count than millenium will not increase the drop time at all. In fact, if they did lengthen the train, it would actually increase the drop time due to the fact that the train will not start its acceleration down the drop until the middle of the train has crested (hence hang time in the front).

Secondly, Millenium force does not maintain an 80 degree fall for 310 feet nor will Maverick maintain 95 all the way down either. Plus a coaster can only see its maximum acceleration due to gravity if it is dropping at 90 degrees. 95 degrees actually acellerates the train slower than if it were 90 but only by a very small amount. In fact, if the drop went to 85 degrees instead of 95. at that point they would be falling at the same rate because both are 5 degrees off of 90 the formula for accel. due to gravity on a ramp is Accel(ft/s^2) = 32*sin(angle).

The only way anyone would be able to compute the drop time would be to graph the exact shape of the drop and plot a best fit line to find the average angle. Then use the above formula to find the average acceleration = a, then find the final velocity using this form. Vf = sqrt(V0^2+2*g*h) when h = height and V0 = speed at the top of lift and g = accel. to gravity which is 32ft/s. then find average speed with V=V0+Vf/2. then the rate of average vertical drop with Vy = V*sin(angle). Lastly, divide the height of the drop by Vy to get total drop time.

I can pretty well assure you the drop time will be far quicker then millenium as the average angle on mavericks drop is much steeper than millenium and the distance it has to fall is far less than our favorite blue giant.
*** Edited 9/8/2006 8:52:06 PM UTC by Kceovaisnt***
*** Edited 9/8/2006 8:54:55 PM UTC by Kceovaisnt***

Thanks, that explains how much goes into finding how long the drop time will be.
That would be another cool stat to have on coasters, just so not to be decieved by height alone.
I came to realize this after riding Goliath and Millennium Force; Goliaths "airtime" at SFMM was noticeably less, because the angle was not nearly steep enough.
Even though Mavericks hill is considerably less, 95 degrees should pack a punch.

Best thing about Maverick - I can ride it with my 7 year old daughter.

Isn't the Horse-shoe turn a first? So really, I don't think anyone has ever experienced it...But it looks fun; almost like a cobra roll on an inverted coaster.

Yeah it does look like fun. They look more like a corkscrew / zero-g roll manuever back to back and mirrored by a 180 degree turn. I don't know if it would be worth laying claim to given their mission statement on this ride.

I think they are going to have a great ride with this one. It's fairly long, and has exciting elements to it. I am happy to see a ride like this one finally show up again. Only negative for me is the horsecollar I will bang my neck on.