More intense launch, #16 or WT?

I know we don't know the speed of 16 yet, but which one do you think will have a more intense launch? I ask this because I have not been on WT yet, and next summer I want to ride the least intense one first. I love G's and can't wait to feel them on #16.

Might want to hit the WT first then. Although WT is pretty intense...First time i been on it, i felt like my guts were going to explode. Maybe just because i ate too much.

#16 will travel at 100+ Mph, so i guess there will be more G's on #16. Although the pullout is huge.

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- Dennis

The first launch on WT is 50MPH. Now double that speed launching in about the same time as WT. That is one intense ride.

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Great Ohio Coaster Club member #335

The launch on 16 looks to be at least twice the length of WT. Wouldn't this make the G's about the same?

As far as I understand (I'm by no means a physics expert) G's are pulled on directional changes, such as the trip up from the launch track to the vertical tower track, and the trip from the tower to the brake run. The length of the launch track really doesn't have much to do with it.

Photonix, hit Wicked Twister first. I'm sure it'll work well as a 'prep' for #16, just like Demon Drop is a good 'prep' for those unsure about Power Tower.

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gravity: down to earth, without the sugar coating.

www.geocities.com/gravityjmb
*** This post was edited by Gravity 12/2/2002 11:46:05 PM ***

Sure, the launches are both launches, but you also have to take into account that WT is inverted and #16 is classic closed-circuit.

I've been on plenty of launch rides, and even though a launch is a launch, an inverted launch is unique. Compare Volcano to Flight of Fear at PKI. Both are launches, but you have to admit that they're a tad bit different.

On inverted, you can feel your legs get pushed back, and on classic, you can feel your arms get thrown back.

Sure, these things have nothing to do with g's, but they are different and some may consider an inverted launch more intense or vice versa just because of that one tiny difference.

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(Insert something clever here)

Trust me.. #16 will make Wicked Twister look like your average chain lift's speed.

Its gonna be a BLUR!

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Panic Attack
FIGHT BACK
http://listen.to/panicattack

I will lay my life on the line to say that #16 will make WT look like dogems. It will be intense. It's like Hypersonic compared to Flight of Fear.

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Love,
The Mole

G's depend on the rate of acceleration. If 16 has double the track, and double the speed (of wt), then the acceleration G's will be the same as WT. It all depends on the duration of the acceleration, the average acceleration.

I think a bean just fell out

No offense, Gravity, but with a name like yours, one would expect you would know what g's are. ;)

Any time an object changes speed or direction (or both), it is being acted on by a force (or more precisely unequal forces). These forces can be generated by any number of things, but are often quantified by comparing them to the most constant force that we are familiar with, gravity. Here on the surface of Earth, the force of gravity pulls every object toward the center of the planet with a force of 9.8 Newtons (this force accelerates falling objects at roughly 32 feet per second every second that it falls or 32 ft/s^2).

So when you talk about "pulling g's", and you want to do it correctly, any time a coaster speeds up or slows down or changes directions, you are experiencing zero g's when you are sitting still or traveling at a constant speed in a straight line. In freefall, you are experiencing 1 g straight down. Anytime you move through a turn or accelerate/decelerate, then you can quantify the amount of force by comparing it to the amount of force that the ground pushes up on your feet when you are standing still (as it opposes the pull of the earth's gravity).

However, coaster people often refer to g-forces as the forces you feel that the train exerts on your body. In this case, you would feel "zero g's" when you just kind-of float in your seat as you fall over a hill at the same rate as the train. This happens on a vertical fall like Demon Drop or a properly executed bunny-hop or (hopefully) a 400'+ tophat. Using this terminology, positive g's would be those forces like a pull-up that force you down into your seat, negative g's would throw you up against the lap bar or shoulder restraint, and lateral g's would push you against the side of the train or your friend beside you.

I hope this helps clarify the subject a bit.

As far as which ride will be more intense, force-wise, we'll have to wait at least for an announcement, or maybe even until we ride it!

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.Jeff said:
Your beans are all going to spill at 424ft in the air... 0-122mph in 2.5sec.. dont tell the point I said this stuff - I'll be removing this post in 5 min.

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Jeff
Webmaster/GTTP - Sillynonsense.com
"Climbing as we fall, we dare to hold on to our fate, and steal away our destiny to catch ourselves with quiet grace" - The Stairs, INXS

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I removed it for you. You do realize that your IP address is recorded when you post here, right?

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Virtual Midway
http://www.virtualmidway.com

Mr. halo. how long have you been studying this? Acceleration due to gravity is NOT measured in Newtons. newtons are a unit in force, gravity is an acceleration and it is measured in meters per second squared but yes it is 9.8.

also you stated that you experience "zero Gs" when standing still, traveling a constant speed in a straight line. Try 1 G! im sitting down typing right now and i can assure i am by no means experiencing airtime. also when in free fall you dont experience 1 G. THATs where you experience zero gs.

Use your corrections wisely and make sure you know what you are saying. Because anytime you try to BS it destroys your credibility.
*** This post was edited by Fluidcoasters 12/3/2002 1:24:27 PM ***

G Force is not really a force, its a mechanical accelleration of any kind plus or minus gravity. On turns, hills, and loops, its centrpetal acceleration. but there are also G forces in launches and brakes. The formula for Centripetal acceleration is V2/r. If you want to calculate Gs, Here is how. First you must know the angle of that point in which you are calculating you can find out by this formula [9.801 - (9.801 x angle / 90)] Just for this purpose call the answer "P"...9.801 meters per second squared is the acceleration due to gravity on earth or 1 G. Then you must calculate the acceleration. there are two different formulas for two kinds of accelerations that are possible on coasters. I'll start with centripetal acceleration [(Velocity squared) / Radius] or it could be linear acceleration [Velocity / Time]. for this purpose call the answer "A". Then you take both P and A and add or subtract depending on whether or not the acceleration is with gravity(+) or against gravity(-). Curving up wards(+), curving downwards(-), Launching Upwards(+), Launching downward(-). Once you add or subtract and get your answer divide it by 9.801 and thats your G force reading.

In response to the posts Gs are involved heavily in launches. Acceleration=Velocity/Time or Acceleration=Distance/Time(squared). so if you dont know the distance of the lauch or the time difference seeing as how it isnt running, then none of you or even me can say what the acceleration or Linear Gs will be or whether wicked twister or 16 will have a greater boost.

Wicked twister cheats a little bit. If you look at the way the LIMs are set up, you'll notice the station section is packed with LIMs. On the other hand, on the rest of the launch the LIMs are more spread out. The LIMs in the station give the powerful boost out of the station. The rest of them just add to the speed without the significant acceleration force.

I don't know how much force WT pulls in it's launch; however Intamin's hydrualic launch is capable of up to 2 Gs. This isn't vary much force, but it's the most sustained lanuch.

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House of Tomorrow: Only technology makes live worth living

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Mr. Halo said:
No offense, Gravity, but with a name like yours, one would expect you would know what g's are. ;)

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I live for irony. ;)

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gravity: down to earth, without the sugar coating.

www.geocities.com/gravityjmb

#16's launch will be more intense, not only becuase is it 2-2.5x faster, but it will do it in less than twice the time to hit the max speed. It may be true that WT goes 0-50 in say 500 feet, while "Dragster" does 0-110+ in 1000, but WT's is in 2 seconds, while "Dragster's" will be in 3 seconds or less.

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Launch: Tophat: Twistage: Brakes...

...Denial is an ugly thing.

2 Gs isnt very much force??

It may not sound like much force but it is a ton of force.

A ride that shoots from 0 to 80 in 2 seconds is pulling 1.8 linear Gs. Thats a HEFTY lauch to me how bout you guys?

Assumuming that this ride is over 400 feet tall requiring 122 mph and launching at 2 Gs exactly, it would go from 0 to 122 mph in 2.8 seconds. If this is true i am so there!
*** This post was edited by Fluidcoasters 12/3/2002 3:46:49 PM ***

Xcelerator gets going 82 mph in 2.3 seconds, and HyperSonic XLC goes 0 to 82 in 1.8 seconds. That has to pull several g's, I don't know if there is a way to figure them out or not. I have to think that #16 will be in the same region.

Wait!!!... Something isnt right... If its going to be lauched at 0 to 122 in 2.8 seconds then the launch would only be 250 feet long. CP Bound, if the launch track is 1000 feet then there is no way that it could be pulling 2 gs. I just did the figures for if it was 1000 feet long and i came up with 0 to 122 in 9.9 seconds... 0.6 Gs That my friends is the same as Superman: The Escape. That could very well be possible. Gah! dont tell me ignorance is bliss.